What is the length and width of a rectangle given by the trinomial r squared - 6r- 55? Use factoring

The length and the width of the rectangle are 11 units and 5 units

Step-by-step explanation:

Let us use the factorization to find the length and the width of the rectangle

∵ The trinomial is r² - 6r - 55

∵ r² = (r)(r)

∵ -55 = (-11)(5)

- Multiply r by -11 and r by 5, then add the products, the sum

   must be equal the middle term of the trinomial

∵ (r)(-11) = -11r

∵ (r)(5) = 5r

∵ -11r + 5r = -6r ⇒ the middle term of the trinomial

∴ r² - 6r - 55 = (r - 11)(r + 5)

- Equate each factor by 0 to find the value of r

∵ r - 11 = 0

- Add 11 to both sides

∴ r = 11

OR

∵ r + 5 = 0

- Subtract 5 from both sides

∴ r = -5 ⇒ rejected because no negative dimensions

∴ The length of the rectangle is 11 units

∵ The area of the rectangle is 55 units²

∵ Area of a rectangle = length × width

∴ 55 = 11 × width

- Divide both sides by 11

∴ 5 = width

∴ The width of the rectangle is 5 units

42.4

step-by-step explanation:

convert to decimal

5x + 5

step-by-step explanation:

you should always add the diagrams and graphs we cannot see. this particular question is kind of borderline because we can make a graph for you.

(f + g)x = -x^2 +3x + 5 + x^2 + 2x

(f + g)x = 5x + 5

the graph of z = 5x + 5 is shown below. always use desmos when in doubt.