HELP NEED HELP ASAP! Find the zeros or roots for the quadratic expression 2x^2-8x-10 must show all work

5 and - 1

Step-by-step explanation:

2x^2-8x-10=0

a=2,b=-8,c=-10

x1=(-b+sqrt(b^2-4ac))/2a

x1 =(-(-8)+sqrt ((-8)^2-4*2*(-10))/2*2

x1=(8+sqrt (64+80))/4

x1 =(8+sqrt (144))/4

x1=(8+12)/4

x1=20/4

x1 =5

x2=(-b-sqrt(b ^2-4ac)) /2 *a

x2=(8-12)/4

x2=-4/4

x2=-1

since both sides equal, there are infinitely many olutions.

we need the options

step-by-step explanation: