Which is the area between the x-axis and y=x from x=3 to x=6

63
45/2
27/2
81

I am going to answer using calculus. Let me know if you instead were looking for an algebraic method. Take the definite integral from 3 to 6 of xdx. [x^2/2]3 to 6= 18-(9/2)= (36-9)/2= 27/2. The area is 27/2.