A transformation is shown in the diagram
Which transformation is shown?
Quadrilateral DEFG is translated to form quadrilateral
D'EFG
Quadrilateral DEFG is rotated to form quadrilateral
D'E'F'G'
Quadrilateral DEFG is reflected to form quadrilateral
D'EFG
Quadrilateral DEFG is dilated to form quadrilateral
D'E'F'G'

Hello! Remember you have to write complete questions in order to find good and exact answers. Here, I'll provide my own figure and explain why I chose option A.

A quadrilateral is any polygon with exactly 4 sides. In the figure below, we have a quadrilateral DEFG with coordinates:

And another quadrilateral D'E'F'G' has the following coordinates:

So the rule is:

So every point of quadrilateral DEFG is translated 5 units to the right in order to get quadrilateral D'E'F'G'. Thus, the correct option is:

Quadrilateral DEFG is translated to form quadrilateral  D'E'F'G'

  5.   y=6; de=7; fg=8

  6.   x=4.2; jl=14.2; mn=13

step-by-step explanation:

when chords cross inside a circle, the product of the segment lengths is a constant.

5. dh×eh = fh×gh

  y = gh = dh×eh/fh = 3×4/2 . . . divide by the coefficient of gh

  y = 6

of course, the total chord length is the sum of the lengths of its segments.

  de = dh +eh = 3+4 = 7

  fg = fh +gh = 2+6 = 8

6. this problem works the same way as the previous one.

  x = lk = mk×nk/jk = 6×7/10 = 4.2

  jl = jk +lk = 10 +4.2 = 14.2

  mn = mk +nk = 6 +7 = 13

comment on chords and secants

you can think of the points h (problem 5) and k (problem 6) as points where the chords meet. a chord is part of a secant line, a line that intersects the circle in two points. one can also consider these points (h or k) to be the points where the respective secant lines meet.

then, the product that is a constant is the product of the distance from the meeting point (h or k) to one circle intersection with the distance from that meeting point to the other circle intersection. for problem 5, the constant is the product hd×he = hf×hg.

it turns out that this rule regarding the products of lengths to points of intersection is also true when the secants intersect outside the circle.

that is, you only need to remember one rule to work both kinds of problems.

the diver is 33 feet below the surface.

step-by-step explanation:

hope this