Two resistors, with resistances R1 and R2, are connected in series. R1 is normally distributed with mean 100 ohms and standard deviation 5 ohms, and R2 is normally distributed with mean 120 ohms and standard deviation 10 ohms. Assume that the resistors are independent. Compute P (R subscript 2 greater than R subscript 1 ). Round your answer to four decimal places.

The probability that R2 is bigger than R1 is P=0.9633.

Step-by-step explanation:

We need to compute the probability that R2 is bigger than R1:

To do this,  we define a new variable Das the difference between the two resistances:

Then,

As R1 and R2 are normal random variables, the properties of D are:

Then, we can calculate the z-value for D=0

answer: 1,380

step-by-step explanation:

1: you turn %15 into a decimal by moving the decimal point two places to the left.

2: and then you multiply .15 by 1,200 , which will get you 180.00

3: from there you will add 180 to 1,200

4: which will get you 1,380

hope it *im kind of slow so idk if my answer is right*

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step-by-step explanation: