Given a real number x and a positive integer k, determine the number of multiplications used to find k x 2 starting with x and successively squaring (to find x2 , x4 , and so on). Is this a more efficient way to find k x 2 than by multiplying x by itself the appropriate number of times?

the solution is h=10 because you add 9 to each side of the equation.

7! = 7×6×5×4×3×2

3! = 3× 2

as 7! is multiple of 3! because 7! contains 3! that is 3× 2 as factor

so 7! /(3! ) = 7× 6× 5× 4

= 42 × 20

= 840

its b) 840✌✌✌

dhruv⭐

yes the total will be same because in both of them the expression.is rearranged but their sign remains the same hence it hss just been shuffled