What values of b satisfy 3(2b + 3)2 = 36?
b = StartFraction negative 3 + 2 StartRoot 3 E...
Mathematics, 05.03.2020 17:41 jaylynC
What values of b satisfy 3(2b + 3)2 = 36?
b = StartFraction negative 3 + 2 StartRoot 3 EndRoot Over 2 EndFraction and StartFraction negative 3 minus 2 StartRoot 3 EndRoot Over 2 EndFraction
b = StartFraction negative 3 + 2 StartRoot 3 EndRoot Over 2 EndFraction and StartFraction negative 3 minus 2 StartRoot 3 EndRoot Over 2 EndFraction
b = StartFraction 3 Over 2 EndFraction and StartFraction negative 9 Over 2 EndFraction
b = Start Fraction 9 Over 2 EndFraction and StartFraction negative 3 Over 2 EndFraction
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