1 point) Let (,) be a function of two variables. Let (,)=(,), and (,)=H(,). Find ′(x) for each of the following cases (your answers should be written in terms of and H). (a) (x)=(x,2): then ′(x)= G(x,2) (b) (x)=(5,x): then ′(x)= H(5,x) (c) (x)=(x, x): then ′(x)= G(x, x)+H(x, x) (d) (x)=(5x, x5): then ′(x)= 5xG(5x, x^5)+5xH(5x, x^5)

it's equivalent, so we can say that its equal.

let's call the denominator x and the numerador is 18 less then denominator, x - 18.

multiply

2.x = 5.(x - 18)

2x = 5x - 90

90 = 5x - 2x

90 = 3x

x = 90/3

x = 30

so:

idk

step-by-step explanation: i just don't

his chances of getting a coin of higher value is 4/19

step-by-step explanation:

answer: options

step-by-step explanation: