The roots of the quadratic equation z^2 + az + b = 0 are -7 + 2i and -7 - 2i. What is a+b?

a+b=249/14

Step-by-step explanation:

z1= [-a+sqrt(a^2-4ab)]/2

z1= [-a-sqrt(a^2-4ab)]/2

z1= -a/2+[sqrt(a^2-4ab)]/2

then,

-a/2=-7

so, a=14

a^2-4ab= -16

b=(a^2+16)/(4a)

b=53/24

therefore, a+b= 249/14

56

step-by-step explanation: