A child, 1 m tall, is walking directly under a street lamp that is 6 m above the ground. If the child walks away from the light at the rate of 20 m/min, how fast is the child's shadow lengthening?

The shadow is increasing with the rate of 4 m/min

Step-by-step explanation:

Consider x represents the length of the boy from the lamp and y represents the length of his shadow,

Given,

The height of boy = 1 m,

The height of lamp = 6 m,

By making the diagram of this situation,

We get two similar triangles one having sides 6 and x+y , and other having sides 1 and y,

Since in similar triangles corresponding sides are in same proportion,

Thus,

Differentiate with respect to t (time),

We have

the answer is a

step-by-step explanation:

answer: c

because if you look at the chart you can see a pattern and compare it to the question he simplify out your

but i think the formula is f(x)=6x