5(-3x - 2) - (x - 3) = -4 (4x +5) + 13

No value for x

Step-by-step explanation:

Step 1: open the bracket

5(-3x - 2) - (x - 3) = -4 (4x +5) + 13

-15x + 10 - x +3= -16x - 20 +13

Step 2: combine like terms

-15x - x + 16x = -20 +13 -10 -3

-16× +16× = -20

0= -20

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

1 and 0

step-by-step explanation: