Which function has two x-intercepts, one at (0, 0) and one at (4, 0)?
f(x) = x(x − 4)
f(x) = x(x + 4)
f(x) = (x − 4)(x − 4)
f(x) = (x + 4)(x + 4)

The function that has two x-intercepts (0,0) and (4,0) is f(x) = x ( x - 4 )

Discriminant of quadratic equation ( ax² + bx + c = 0 ) could be calculated by using :

From the value of Discriminant , we know how many solutions the equation has by condition :

D < 0 → No Real Roots

D = 0 → One Real Root

D > 0 → Two Real Roots

Let us now tackle the problem!

If the function f(x) = ax² + bx + c has x - intercept at ( 0 , 0 ) , then:

If the function f(x) = ax² + bx + c has x - intercept at ( 4 , 0 ) , then:

From the above results it can be concluded that the function is

If a = 1 , then :

Grade: High School

Subject: Mathematics

Chapter: Quadratic Equations

Keywords: Quadratic , Equation , Discriminant , Real , Number

135 is your answer

step-by-step explanation:

try 180 times three then divide that number by 4 (sides) to get your answer. im glad to : )