Solve (x + 5 < 4) ∩ (x - 3 > -6)

∅ i.e empty

Step-by-step explanation:

(x + 5 < 4) ∩ (x - 3 > -6)

Let A represent the set (x + 5 < 4)

Let B represent the set (x - 3 > -6)

For set A:

x + 5 < 4

subtract 5 from both side

x < 4 —5

x < —9

Possible values of x are - 10, - 11, - 12,...

A = {- 10, - 11, - 12,...}

For set B:

x - 3 > -6

Add 3 to both side

x > -6 + 3

x > - 3

Possible values of x are - 2, - 1, 0,...

B = {- 2, - 1, 0,...}

A= {- 10, - 11, - 12,...}

A ∩ B = ∅ i.e empty

Therefore, (x + 5 < 4) ∩ (x - 3 > -6) is ∅ i.e empty

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v

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step-by-step explanation: