If 2a+b=3,find the value of 8a³+b³+18ab

27

Step-by-step explanation:

A sum of cubes factors as

a³ + b³ = (a + b)(a² - ab + b²)

Factor the sum of cubes 8a³ + b³

8a³ = (2a)³, thus

8a³ + b³

= (2a)³ + b³

= (2a + b)(4a² - 2ab + b²)

We now have the right side as

(2a + b)(4a² - 2ab + b²) + 18ab ← substitute 2a + b = 3

= 3(4a² - 2ab + b²) + 18ab

= 12a² - 6ab + 3b² + 18ab ← collect like terms

= 12a² + 12ab + 3b² ← factor out 3 from each term

= 3(4a² + 4ab + b²) ← perfect square

= 3(2a + b)² ← substitute 2a + b = 3

= 3 × 3²

= 3 × 9

= 27

3; 9 is 8 to -4

step-by-step explanation: