*SOMEONE WHO CAN SIMPLY ORDER INTERVALS!*

The table represents the height of a rock thrown off the side of a bridge that is 96.44 feet above ground level for the first 0.60 seconds. Find the average rate of change for each interval and order the intervals from least to greatest rate of change.

Time (seconds) (left) / Height (feet)(right)

0.00 / 96.44

0.10 / 97.60

0.30 / 98.57

0.60 / 98.30

2.5 seconds.

Step-by-step explanation:

Find the value of t when the height is 28 feet:

-16t^2 + 56t + 4  = 28

-16t^2 +  56t - 24 = 0

-8(2t^2 - 7t + 3) = 0

-8(2t - 1)(t - 3) = 0

t = 0.5,  3 seconds.

So on the upward journey the rock is at 28 feet at 0.5 second after the throw and at 3 seconds it is at 28 feet again  while it is falling back.

Therefore the period when it is at least 28 feet above the ground is 3.0 - 0.5 = 2.5 seconds.

yes

step-by-step explanation:

yes