X²+6x+3=0

How do I solve this

The exact roots are -3 + √6,  - 3 - √6

or  -0.55, -5.45 to the nearest hundredth.

Step-by-step explanation:

x² + 6x + 3 = 0

We complete the square:

x^2 + 6x = -3

(x + 3)^2 - 9 = -3

(x + 3)^2 = 6

x + 3 = +/- √6

x =  -2 + √6,  - 3 - √6.

if a = 1,   and b = 2, then the answer is 47.99999999. if you round that to the nearest whole number, the answer is 48.

δabc ≅ δdcb by sas because

db ≅ ac . . given (side)

bc ≅ bc . . reflexive property (side)

∠dbc ≅ ∠ acb . . alternate interior angles where transversal bc crosses parallel lines bd and ac (included angle)