What is the greatest possible whole-number value of the congruent side lengths?
9 cm
10 cm
14 cm
15 cm

In an obtuse triangle, the square of the longest side is greater than the sum of squares of the other two sides. So the equal legs must have a length  

L^2 + l^2=2l^2

14^2+14^2=20^

196+196=400

392=400

14cm is the greatest

x = 2

step-by-step explanation:

if sr parallel to ba then the sides bc and ac are in proportion, that is

= ← substitute values

= ( cross- multiply )

27x = 6(4x + 1)

27x = 24x + 6 ( subtract 24x from both sides )

3x = 6 ( divide both sides by 3 )

x = 2