Suppose all permutations of rankings of four students a, b, c, and d are equally likely. Let A be the event that a ranks ahead of c and B the event that b ranks ahead of d. Determine if A and B are independent.

step-by-step explanation:

well if you round, things become much more simple. round 5.95 to 6, 4.25 to 4, and 1.05 to 1. now, add 6+4+1 and that would equal 11. so the items together would equal to about $11.

7 is the median   7.875 is the mean

step-by-step explanation:

3,4,5,6,8,11,13,13