Try to visualize the set of all points 1x, y, z2 in a coordinate space that are equidistant from the points P10, 0, 02 and Q10, 3, 02. Use the Distance Formula to find an equation for this surface, and observe that it is a plane.

Y plane at y=3/2 contains all the points which will be equidistant from both points P and Q.

Step-by-step explanation:

As the complete question is not readable, the question is found online and is attached herewith.

By the distance formula, as the point R with coordinates x,y,z is equidistant from P and Q thus

So the y plane at y=3/2 contains all the points which will be equidistant from both points P and Q.

see attached

step-by-step explanation:

given the function as;

write the equation replacing f(x) with y

form   and fill a table containing values of y with corresponding values of x

you can take a range for   values of x as -3≤x≤3

solving for x=-3

for x=-2

repeat the same procedure to get the values of y for the remaining ,x=-1 to x=3

plot the values of y against values   of x and obtain the following graph