Find the velocity and acceleration vectors and the equation of the tangent line for the following curve, at the given value of t. r(t) = (cos(t))i + (sin(6t))j, at t = 0

ab will be equal to

hello from mrbilldoesmath!

answer:   x^2 + y^2 = 1024

discussion:

the equation of a circle with center (h,k) and radius "r" is

(x-h)^2 + (y-k)^2 = r^2.

in our case

(x-0)^2 + (y-0) ^2 = 32^2 = 1024

you,

mrb

sorry not knowing about that