The perimeter of rectangle is 44 inches. if the length of the rectangle is 7 more than half its width. what is the area of the rectangle . PLSS HELP

The area of the rectangle is 120 inches squared.

Step-by-step explanation:

First, identify what you know:

1) The perimeter of the rectangle is 44 inches.

2) The length of the rectangle is 7 more than half its width.

To solve the area of this rectangle, we need to know the width and length of the shape. First, it's important that we know the formula for finding the perimeter, and the area of a rectangle.

Perimeter = 2 x (L + W)

Area = L x W

Now, we can create a formula to demonstrate our problem

Perimeter (44 inches) = 2 (W + ((1/2 x W) + 7)))

Now, we can divide both sides in half, to simplify.

22 inches = (W + ((1/2 x w) + 7))

If you input the values 12, and 10, you'll see that it works!

22 inches = (10 + ((1/2 x 10) + 7))

22 inches = (10 + (5 + 7))

22 inches = (10 + 12)

122 inches = 22 inches

Now, using the Area formula, we can solve for the area of the rectangle, since we know the length and the width.

A = L x W

A = 12 X 10

A = 120 inches squared.

the required function is .

step-by-step explanation:

from the given table it is noticed that the graph passing through (-3,7), (0,4), (3,1) and (8,-4).

it is a linear function because the value of y is decrease by one as the value of x increase by 1.

the slope of the function is

the slope of the function is -1 and the y-intercept is 4.

the slope intercept form is

where, m is slope and b is y-intercept.

therefore the required function is . the graph of this function is shown below.

(-5,-28)

i graphed to on desmos.