Every day at noon, a bus leaves for Townville and travels at a speed of x kilometers per hour. Today, the bus left 30 minutes late. If the driver drives 7/6 times as fast as usual, she will arrive in Townville at the regular time. If the distance to Townville is 280 kilometers, what is the value of x

Step-by-step explanation:

Given that every day at noon, a bus leaves for Townville and travels at a speed of x kilometers per hour. Today, the bus left 30 minutes late.

If the driver drives 7/6 times as fast as usual, she will arrive in Townville at the regular time.

If correct time leaves then distance = time *speed

280 = t*x where t is the time in hours

Or t = 280/x

Now speed changes to 7x/6 while time changes to (t-1/2)

So 280 = (t-1/2) 7x/6

x = 80 km per hour

can someone answer this question plz

step-by-step explanation:

62.5 paisa

step-by-step explanation:

4000*70 = 280000

280000-(2000*90) = 100000

4000-2400 = 1600

100000/1600 = 62.5

( give brainliest)