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![\frac{1}{2} \int\limits^{\frac{\pi}{5}} _0 {(3\ sin(5\theta))^2} \, d\theta\\\\ =\frac{9}{4} \int\limits^{\frac{\pi}{5}} _0 {(1-cos(10\theta))} \, d\theta\\\\ =\frac{9}{4} [\theta-\frac{sin(10\theta)}{10}]^\frac{\pi}{5}} _0 \\\\ =\frac{9\pi}{20}](/tpl/images/0275/8872/28662.png)
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Area enclosed by one loop of r=3sin(5theta)...
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