Problem PageQuestion It takes an older pump twice as long to drain a certain pool as it does a newer pump. Working together, it takes the two pumps hours to drain the pool. How long will it take the newer pump to drain the pool working alone? Do not do any rounding.

It will take 6 hours for the new pump to drain the pool.

Step-by-step explanation:

As the complete question is not given, the complete question is found online and is attached herewith

Let the rate of new pump is given as x=W/t_1

Let the rate of the old pump is given as y=W/t_2

it is given that the time t_2=2t_1

So by substituting the values of t_2 in the rate equation of y

y=W/2t_1

y=(W/t_1*2)=x/2

Also the total rate of both the pumps is given as W/t3 where t3 is given as 4 hours so the equation becomes

x+y=W/4

x+x/2=W/4

3x/2=W/4

As x=W/t_1

3W/2t_1=W/4

Now as W is same on both sides so

3/2t_1=1/4

12=2t_1

t_1=6 hours

So it will take 6 hours for the new pump to drain the pool.

answer: what in the world is this

step-by-step explanation:

x² + 3x + 7 = 0       [ax² + bx + c]

a = 1

b = 3

c = 7

quadratic formula:

    (+/- is this ±)

plug in the numbers into the variables

your answer is a