4.The amount of atmospheric radiation to which a person is exposed to while flying by jet across the country is considered a random variable with an approximate normal distribution. On a New York to Los Angeles flight, this distribution has an assumed mean of 5.2 mrem, with a standard deviation of 0.615. What is the probability that a randomly selected individual on such a flightis exposed to more than 6.0 mrem (millirem) of atmospheric radiation?

0.097 is the probability that a randomly selected individual is exposed to more than 6.0 mrem of atmospheric radiation.              

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 5.2 mrem

Standard Deviation, σ = 0.615

We are given that the distribution of atmospheric radiation is a bell shaped distribution that is a normal distribution.

Formula:

P(flightis exposed to more than 6.0 mrem)

P(x > 6.0)

Calculation the value from standard normal z table, we have,  

0.097 is the probability that a randomly selected individual is exposed to more than 6.0 mrem of atmospheric radiation.

what do you need me to answer?

step-by-step explanation:

x > 1.3

step by step:

8.5−0.9x> 9.8−1.9x

step 1: simplify both sides of the inequality.

−0.9x+8.5> −1.9x+9.8

step 2: add 1.9x to both sides.

−0.9x+8.5+1.9x> −1.9x+9.8+1.9x

1x+8.5> 9.8

step 3: subtract 8.5 from both sides.

1x+8.5−8.5> 9.8−8.5

1x> 1.3

step 4: divide both sides by 1.

1x/1 > 1.3/1