A team made 53 successful shots. They were a combination of 1- and 2- point shots. The team scored 88 points in all. What's the number of each type of shot?

the team scored 18 (1 - point shot) and 35 (2 - point shots).

Step-by-step explanation:

Let x represent the the number of

1- point shot that the team made.

Let y represent the the number of

2- points shot that the team made.

The team made 53 successful shots. They were a combination of 1- and 2- point shots. This means that

x + y = 53

The team scored 88 points in all. This means that

x + 2y = 88- - - - - - - - - - - -1

Substituting x = 53 - y into equation 1, it becomes

53 - y + 2y = 88

- y + 2y = 88 - 53

y = 35

x = 53 - y = 53 - 35

x = 18

area = length x width

length = 2 x width

32 = 2 x width x width

32 = 2 x width^2

36 = width ^2  

width = 6

length = 12

area is 32

perimeter = 2 x 12 + 2 x 6 = 24 + 12 = 36

step-by-step explanation:

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3