A box contains 1.0 red chips, 20.bluechips, and 30 green chips. ll5 chrps are orawn lrom the box, find the probability of drawing the indicated chips

A. all blue
B. at least 1 green
C. at most 1 red

Step-by-step explanation:

Let S be the sample space of an experiment and E is an event associated with the experiment.

Let n(S) and n(E) denote the number of element in S and E.

P(E) is the probability of an event E

The number of elements on the sample space ;

n(S) = n(r) + n(b) + n(g) = 10 + 20 + 30 = 60

Hence, the event of drawing 5chips from the box n(S) = C(60,5)

A) probability of drawing 5chips from the box which are all blue ;

P(E) = n(E) / n(S) = 20C5 x 40C0 / 60C5 = 0.0028

by combination method ; nCr = n!/r!(n - r)!

B) the probability of drawing the indicated chips at least 1 green ;

Application of the binomial formula comes in ; nCr x p^r x q^n-r

= P(E) = 1 - p(x <1) = 1 - po = 1 - 30C0 x 30C5 / 60C5

= 0.9739

C)  the probability of drawing the indicated chips at most 1 red;

P(E) = p(no red) + p(one red)

= 10C0 x 50C5 + 10C1 x 50C4 / 60C5

= 0.8096

answer: sherk

step-by-step explanation:

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step-by-step explanation: