Interested in the number of hours a day the typical student studies at his university, Paul decides to form several samples of students and interview each sample at a different time during the semester, including during the final exam period. Which requirement for probability sampling could Paul be violating

unbiased sample values

Step-by-step explanation:

Unbiased sampling involves eliminating any form of bias in the method of selection of participants in a study in order to draw a conclusion about the population.

Paul had introduced bias in the sampling that out to look at the number of hours a day the typical student studies by introducing the variable of studying during the final exam period.

Most likely all student will study during the final exam period. This will not truly represent the study pattern of the sample population and equal chance of selection of study hours of the students. Hence paul had violated the requirement of unbiased sample values for probability sampling by not doing a random selection or systematic random selection

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2

it’s supposed to be -4+45=41

step-by-step explanation: