A set of different sized recatangles have the same area. one has a length of 4cm and width of 12cm . what is the lenght of a rectangle with width of 3cm.

The length of the 2nd rectangle is 16 cm.

Step-by-step explanation:

Given,

1st rectangle of having length (L) = 4 cm and width (B) = 12 cm

2nd rectangle of having width = 3 cm

They are of same are.

To find the length of the 2nd rectangle

Formula,

The area of rectangle = L×B sq cm

Area of 1st rectangle = 12 × 4 sq cm = 48 sq cm

According to the problem,

Length × 3 = 48

or, length = cm = 16 cm

The length of the 2nd rectangle is 16 cm.

L = 16cm

Step-by-step explanation:

Given the rectangles have the same area,

Area = length x width

Area of the one with length 4cm and width 12cm

= L x w

= 4 x 12

= 48 square centimeters

Now , length of rectangle with width 3cm ?

Recall that the rectangles have the same area.

So,

48 = L x 3

Divide both sides by 3

48/3 = L x 3/3

16 = L

L = 16cm

The Length of a rectangle with width of 3cm is 16cm

the multiples of 15 are 15, 30,45, 60, 75, 90, 105, 120, 135, 150, 165, 180, 195,   210, 225, 240, 255, 270, 285, 300, 315, 330, 345, 360, 375,   390, 405, 420, 435, 450, 465, 480, 495, 510, 525, 540, 555, 570, 585, 600, 615, 630, 645, 660, 675, 690, 705, 720, and 735.

the factors of 15 are 1, 3, 5, and 15.

hope that , fam!

-une, your fren : )