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![2 sin \frac{\pi }{4} sin \frac{\pi }{6}=cos (\frac{\pi }{4}-\frac{\pi }{6})-cos (\frac{\pi }{4} +\frac{\pi }{6} )\\=cos (\frac{3 \pi-2 \pi }{12} )-cos (\frac{3 \pi+2\pi}{12} )\\=cos (\frac{\pi }{12} )-cos( \frac{5 \pi}{12} )\\sin \frac{ \pi}{4} sin\frac {\pi}{6}=\frac{1}{2}[cos \frac{\pi}{12} -cos \frac{5 \pi}{12} ]](/tpl/images/0538/5177/0c66e.png)
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sin pi/4sinpi/6 = 1/2[__pi/12-cos5pi/12]...
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