What is the equation of a line parallel to y=-2x+10 that contains (6,8)

y=-2x+20

Step-by-step explanation:

Line is parallel to y=-2x+10,then slope that line is - 2=k.

A(6,8).. x1=6,y1 =8

y-y1=k(x-x1)

y-8=-2(x-6)

y-8=-2x+12

y=-2x+12+8

y=-2x+20

correct answer is option b.

step-by-step explanation:

the true statement about geometric figure is option b that is one line can be drawn through all three points.

if three points are on the same plane, they can be connected by a line.