A line passes through point (-2, 5) and has a slope of . Points A(x, 3) and B(-2, y) lie on the line.
The value of x is
, and the value of y is
.

The question is incomplete. The complete question is here.

A line passes through point (-2, 5) and has a slope of 2/3. Points A(x, 3) and B(-2, y) lie on the line.

The value of x is ___, the value of y is ___.

The value of x is -5, and the value of y is 5

Step-by-step explanation:

The form of a linear equation is y = m x + b, where

∵ The slope of the line is

∴ m =

∵ The form of the equation is y = m x + b

∴ y =   x + b

- Substitute x and y by the coordinates of a point on the line

∵ The line passes through point (-2 , 5)

∴ x = -2 and y = 5

∵ 5 =   (-2) + b

∴ 5 =   + b

- Add to both sides

∴ = b

∴ y = x +

∵ Point A (x , 3) lies on the line

- Substitute y by 3 to find x

∴ 3 = x +

- Subtract from both sides

∴ =   x

- Divide both sides by  

∴ -5 = x

∴ The value of x = -5

∵ Point B (-2 , y) lies on the line

- Substitute x by -2 to find y

∴ y = (-2) +

∴ y =   +  

∴ y =  

∴ y = 5

∴ The value of y = 5

care to share were the trapezoid shown is ?

yes

step-by-step explanation:

so of course you want to start by plugging the 5 in which goes to 7(5)+3(5)=50 because 7*5=35 and 3*5=15 and then add them together, then plug in the 5 to the other equation as well 9(5)+5=50 because 9*5= 45 and then add 5 and so yes they are equivalent.