Plz solve this
ans = 4400

The total surface area of the solid is 4651 sq cm

Step-by-step explanation:

Given,

The diameter of the base = 16 cm

Length of the cylindrical part (h) = 75 cm

The height of the solid = 90 cm

So, the radius of the base(r) = cm = 8 cm

The height of the cone = 90 - 75 cm = 15 cm

The slanting height(l) of the cone = cm = 17 cm [ by Pythagoras theorem]

To find the total surface area of the solid

The solid consists of two separate solids that are a cylinder and a cone.

So, total surface area (TSA) of the solid = TSA of cylinder + TSA of cone

To find the TSA pf cylinder

Formula

TSA of cylinder = 2πrh +2πr

=2πr(r+h)

=2 ××8×(8+75) sq cm

= 4173.7 sq cm (approx)

Again,

To find the TSA pf cone

Formula

TSA of cone = πrl +2πr

=πr(l+2) sq cm

= ×8×(17+2) sq cm

= 477.7 sq cm (approx)

Hence, total surface area (TSA) of the solid = 4173.7 sq cm + 477.7 sq cm

= 4651.4 sq cm

you should at least use a calculater

step-by-step explanation:

given that triangle abc is transformed two times to get triangle

a"b"c"

first abc is transformed in to a'b'c' as follows:

the coordinates of a are (1,-1) and transformed into a'(-1,1)

similarly b (4,-2) became b'(-4,2) and

c(7,-2) became c'(-7,2)

i.e. (x,y) becomes (-x,-y)

this is nothing but reflection about a point here origin.

thus first transformation is reflection on the origin.

next is exactly shifting 3 units down

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