Your bathroom scale sits on a ramp making an angle of 20 degrees with the (perfectly horizontal) ground. When you stand on the scale, will the weight it reports be higher than your actual weight, lower than your actual weight, or correct?

Step-by-step explanation:

If the bathroom scale make an angle of 20°

Then, we need to resolve it to the vertical axis

W=mg

Then weight on the vertical axis is

W=W•Cos20

Since cos20 is less than 1

The weight is lower than it's actual weight because the weight that will be recorded on the scale is the normal weight and which is

N=W•Cos20

N=0.94W

%reduction = (actual weight-measure weight)/actual weight ×100

%reduction= (W-0.94W)/W × 100

%reduction=0.06W/W× 100

℅reduction =6%

It will be reduce by 6% of his original weight

b) well because you get well

y -5 = (-1/4)(x + 8)

step-by-step explanation: