The graph of y ≤ 3x + 1 and y ≥ –x + 2? Check all that apply. 1.The slope of one boundary line is 2.
2.Both boundary lines are solid.
3.A solution to the system is (1, 3).
4.Both inequalities are shaded below the boundary lines.
5.The boundary lines intersect.

2.Both boundary lines are solid.

3.A solution to the system is (1, 3).

5.The boundary lines intersect.

Step-by-step explanation:

The give inequalities are:

The slopes of the first boundary line is 3 and the second is -1

Therefore the first statement is false.

Both boundary lines are solid because they contain the equality type of inequality.

The second statement is true.

(1,3) is a solution of both inequalities, because it is in the solution region

since it satisfies both inequalities.

The 3rd statement is true.

The second inequality is shaded above the boundary line because the origin does not satisfy this inequality..The two slopes are not the same so the boundary lines will intersect.

hope it

step-by-step explanation:

x^(1/6) · x^(1/6) · x^(1/6)   ·x^(1/6) = x^(4/6)   since we add the exponents

4/6 can be simplified to 2/3

the simplified form is x^(2/3)