The area of a rectangle is 42 ft', and the length of the rectangle is 5 ft more than double the width. Find the dimensions of the rectangle.
Length: Ift

Length of the rectangle is 12 ft and width is 3.5 ft

Step-by-step explanation:

⇒ 42 = (5 + 2x)x

⇒ 42 = 5x + 2x²

⇒ 2x² + 5x - 42 = 0

⇒ 2x² + 12x - 7x - 42 = 0

⇒ 2x(x + 6) - 7(x + 6) = 0

⇒ (2x - 7)(x + 6) = 0

∴ x = -6, 7/2 (ignore the negative value)

⇒ Width is 3.5 ft

∴ Length is 5 + 2 × 3.5 = 12 ft

1. minimum

2. 6400

3. eight

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