The plane y=1y=1 intersects the surface z=x4+5xy−y4z=x4+5xy−y4 in a certain curve. Find the slope of the tangent line of this curve at the point P=(1,1,5)P=(1,1,5). m=m=

so slope of the tangent line to the Curve at the point P = (1,1,5) is 9

Step-by-step explanation:

given:

z=x^4+5xy−y^4

so,

δz/δx = (4x^3+5y-0)

(δz/δx)_(1,1) = m = 4(1)^3 +5(1)

          =  9

so slope of the tangent line to the Curve at the point P = (1,1,5) is 9

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i ran through it by the other answer is wrong

5+2x=a

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