Mathematics, 10.03.2020 00:22 jjortiz3137

What is the product? 6 (x squared minus 1) times StartFraction 6 x minus 1 Over 6 (x + 1) EndFraction 6(x – 1)2 6(x2 – 1) (x + 1)(6x – 1) (x – 1)(6x – 1)

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Evaluate 8x2 + 9x − 1 2x3 + 3x2 − 2x dx. solution since the degree of the numerator is less than the degree of the denominator, we don't need to divide. we factor the denominator as 2x3 + 3x2 − 2x = x(2x2 + 3x − 2) = x(2x − 1)(x + 2). since the denominator has three distinct linear factors, the partial fraction decomposition of the integrand has the form† 8x2 + 9x − 1 x(2x − 1)(x + 2) = correct: your answer is correct. to determine the values of a, b, and c, we multiply both sides of this equation by the product of the denominators, x(2x − 1)(x + 2), obtaining 8x2 + 9x − 1 = a correct: your answer is correct. (x + 2) + bx(x + 2) + cx(2x − 1).

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What is the product? 6 (x squared minus 1) times StartFraction 6 x minus 1 Over 6 (x + 1) EndFractio...

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