In the xy, y-plane, the parabola with equation y = ( x− 11)^2y=(x−11) 2 y, equals, (, x, −, 11, ), squaredintersects the line with equation y = 25y=25y, equals, 25 at two points, AAA and BBB. What is the length of \overline{AB} AB start overline, A, B, end overline?

10 units

Step-by-step explanation:

Allow me to revise your question for a better understanding.

"In the xy-plane, the parabola with equation y = (x − 11) ² intersects the line with equation y = 25 at two points, A and B. What is the length of AB"  

Here is my answer

Because the  parabola intersects the line with equation y = 25  Substituting y = 25 in the equation of the parabola y = (x - 11)², we get

25 = (x - 11)²

<=>x - 11 = ± 5  

<=>

Thus A(16, 25) and B(6, 25) are the points of intersection of the given parabola and the given line.

So the length of AB = √[(16 - 6)² + (25 - 25)²]

= √100 = 10 units

- "runner b is moving at a slower rate."

- "the graphs shown are graphs of distance(km) against time(min).

the slopes of this graphs are are given by:

slope = (change in y)/(change in x)

= (change in distance)/(change in time)

this is the formula for finding the speed. so, the slope of these graphs represent the speed of the runner.

taking each division in the graph to represent 1 on both axis:

runner a ⇒ speed = (2-0)/(1-0)

= 2/1

= 2 km/min

runner b ⇒ speed = (3-0)/(3-0)

= 3/3

= 1 km/min

this shows that   runner b is moving at a slower rate."

he has now walked a total of what?

if i know what this is maybe i can

step-by-step explanation: