A particular baseball diamond is actually a square with 7575-foot sides. What is the distance from home plate to second base? Express the answer in simplified radical form. Then find a decimal approximation.

 feet.

Step-by-step explanation:

Please find the attachment.

We have been that a particular baseball diamond is actually a square with 75-foot sides.

We can see that distance from home plate to second base would be equal to hypotenuse with each leg of 75-ft.

We will use Pythagoras theorem to find the distance x as:

Now, we will take positive square root of both sides as:

Therefore, the exact distance from home plate to second base is feet or approximately 106.07 feet.

answer: the price of one pound cabbage = $ 0.8

the point (10,8) represents that the cost of 10 pounds cabbage is $ 8

step-by-step explanation:

since, here is a proportional relation between the number of pounds of cabbage (x) and the price in dollars (y).

therefore, we can write,

⇒ y = k x

where k is the constant of proportionality.

now, point (5,4) is in the line.

thus, it will satisfies the above equation of line.

⇒ 4 = 5 k

⇒ k = 0.8

thus, the equation of the line is,

y = 0.8 x

a) for x = 1,

y = 0.8

therefore, the cost of one pound of cabbage is 0.8 dollars.

b) in the below graph (10,8) represents that the cost of 10 pounds of cabbage is 8 dollars.

6 meters

step-by-step explanation: