A survey measures the motivation, attitudes, and study habits of freshman in college. Freshmans’ scores on this survey range from 0 to 200 and follow (approximately) a Normal distribution, with mean of 110 and standard deviation σ = 20. You suspect that the next group of freshman will have a mean μ, which is different from 110 because they are often excited yet anxious about leaving college. To verify your suspicion, you test the hypotheses H0: μ = 110, Ha: μ ≠ 110 You give the survey to 50 high school seniors who are incoming freshman and find their mean score. Suppose you observed the same sample mean of 115.35, but based on a sample of 100 freshman students. What would the corresponding P-value be?

a. 0.0074
b. 0.9926
c. None of the answers are correct
d. 0.0037

Option A) 0.0074    

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 110

Sample mean, = 20

Sample size, n = 100

Alpha, α = 0.05

Population standard deviation, σ = 115.35

First, we design the null and the alternate hypothesis

We use two-tailed z test to perform this hypothesis.

Formula:

Putting all the values, we have

Now, we calculate the p-value from the standard normal table.

P-value  = 0.0074

Thus, the correct answer is

Option A) 0.0074

answer is d-29

step-by-step explanation:

since you didn't include the picture, i can give you the description so you know how to pick the correct answer. the third quartile of a data is always shown in a box plot. in the middle of your graph should be a box. the third quartile is the value that goes with the far right edge of the box.

konichiwa~! my name is zalgo and i am here to answer your anime-related question today. more than likely, kirishima would kill izuku, marry mino and kiss momo. all of this would be my opinion by the way. (and i am also a weeb lol)

i hope this you! : d

stay and stay proud! " - zalgo

(and do you think you can mark me as brainliest? i'd greatly appreciate it! arigato~! )