Mathematics, 10.03.2020 08:17 HockeyBlockpk7039

The circle touches the sides of AABC, AB, BC and
CA at points P, Q and R respectively. Prove that:
AP+BQ + CR = PB + QC + RA= (AB + BC + AC.)

Answers: 2

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The circle touches the sides of AABC, AB, BC and
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More questions: Mathematics Another questions

The circle touches the sides of AABC, AB, BC andCA at points P, Q and R respectively. Prove that:AP+BQ + CR = PB + QC + RA= (AB + BC + AC.)

Answers

Another question on Mathematics

The circle touches the sides of AABC, AB, BC and
CA at points P, Q and R respectively. Prove that:
AP+BQ + CR = PB + QC + RA= (AB + BC + AC.)