My Notes A spring has a natural length of 22 cm. If a 29-N force is required to keep it stretched to a length of 30 cm, how much work W is required to stretch it from 22 cm to 26 cm

W = 0.058 J

Step-by-step explanation:

given data

natural length = 22 cm

force = 29 N

length = 30 cm

stretch = 22 cm to 26 cm

solution

force F = K x  .....................1

K is spring constant and x is length

Δx = 30 - 26

Δx = 4 cm = 0.4 m

and

F = Kx   ..............2

29 = K(0.4)

K =

K = 72.5

so here

required work to stretch spring

W = 0.5 × K  × Δx²   ...................3

but here

Δx = 26-22 = 4 m = 0.04

and

W = 0.5 × 72.5  × 0.04²

W = 0.058 J

stew reads at the fastest rate of 265 words per minute.

step-by-step explanation:

it's a given that felicia reads at 260 word per minute and on connie's graph we can see that she reads 200 words per minute. since stew's table tells us that he read 795 in 3 minutes, we can divide 795 by 3 to find out how many words he reads per minute.

795/3 = 265

stew reads 265 words per minute - he reads at the fastest rate since felecia reads at 260 words per minute and connie reads at 200 words per minute.

stew (265) > felecia (260) > connie (200)

ok

step-by-step explanation: