A professional basketball team made 37.9% of its three-point field goals in one season. If 80 three-point field goal attempts are randomly selected from the season, what is the probability that more than 35 were made

And we can use the complement rule like this:

And we can use the followin excel code and we got:

"=1-BINOM.DIST(35;80;0.379;TRUE)"

The other way to solve the problem is with the normal approximation:

And we can use the z score given by:

And we got:

And using the complement rule we got:

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

Let X the random variable of interest, on this case we now that:

The probability mass function for the Binomial distribution is given as:

Where (nCx) means combinatory and it's given by this formula:

And we want to find this probability:

And we can use the complement rule like this:

And we can use the followin excel code and we got:

"=1-BINOM.DIST(35;80;0.379;TRUE)"

The other way to solve the problem is with the normal approximation:

And we can use the z score given by:

And we got:

And using the complement rule we got:

see below

step-by-step explanation:

7.   there are 10 data points in the set.   the middle point is between 5 and 6.   the middle point in the top half is 8   and the middle point in the bottom half is 3. to find the iqr , take point 8 and subtract point 3

mid term   point 8 = 100   point 3 = 88

iqr = 100-88 = 12

final   point 8 = 93   point 3 = 78

iqr = 93 - 78 = 15

the final has the greatest iqr

6.   b - there is a high data value that causes the data set to be asymmetrical for the males: the data for males are high and asymmetrical .   there is an outlier for the males that skews the data

5.   the   iqr is a better measure of spread for the movies and basketball games.   since the basketball game has an outlier, we do not want to use standard deviation for measurement.  

3.   the exam median is much higher than the class median.   the median line is farther to the right on the exams

2.   there is no way to tell what the means are from the box and whisker plots.  

answer: 0,6

step-by-step explanation:

this would make it the y intercept.