Which linear function has the same slope as the one that is represented by the table? x y Negative one-half One-fifth Negative one-fifth StartFraction 7 Over 50 EndFraction One-fifth StartFraction 3 Over 50 EndFraction One-half 0 y = negative one-half x + StartFraction 1 Over 10 EndFraction y = negative one-fifth x + one-half y = one-fifth x minus one-half y = one-half x minus StartFraction 1 Over 10 EndFraction

the answer is c: divide the arc's degree measure by 360°, then multiply by the circumference of the circle.

step-by-step explanation:

we have

using a graphing tool

see the attached figure

this is a quadratic equation (vertical parabola) open up

the vertex is a > vertex

the domain of the function is all real > interval (-∞,∞)

the range of the function is the > [-6.125,∞)

the function has two x->   and

the function is increasing over the > (0.25,∞)

the function is decreasing over the > (-∞,0.25)