Consider the function f(x) = 3x and the function g, which is shown below.
g(x)=f(x)-2=3^x-2
How will the graph of g differ from the graph of f?

B. The graph of g is the graph of f shifted 2 units down

Step-by-step explanation:

Graph of Functions

We have two functions:

f(x)=3^x

g(x)=3^x-2

Since g(x)=f(x)-2 it will be represented as an identical graph as that for f(x), but vertically displaced 2 units down. Let's check it by plugging some points

f(0)=3^0=1

g(0)=3^0-2=-1

f(1)=3^1=3

g(1)=3^1-2=1

f(3)=3^3=27

g(3)=3^3-2=25

We can notice the values of g(x) are always 2 units below f(x), thus the correct answer is

B. The graph of g is the graph of f shifted 2 units down

366

step-by-step explanation:

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation: