2x2-x-6 = 0
What is one solution to the equation?

x1=2 and x2 =-3/2

Step-by-step explanation:

2x^2-x-6=0 (quvadratic equation)

a=2, b=-1, c=-6

x1=(-b+sqrt(b^2-4ac))/2a

x1=(-(-1)+sqrt((-1)^2 - 4*2*(-6)))/2*2

x1 =(1+sqrt (1+48))/4

x1= (1+sqrt(49))/4

x1 =(1+7)/4

x1=8/4

x1=2

x2=(-b-sqrt(b^2-4ac))/2a

x2=(1-7)/4

x2=-6/4

x2=-3/2

answer: 48

just remember to use pemdas:

parentheses

expressions

multiplication

division

addition

subtraction

step-by-step explanation:

ok one would be money, and the other would be refreshments or something similar. if each bag of popcorn is 5.00 and each drink is half of that that means drinks are 2.50 the proper way to do that would to look and see how much of each you can buy without exceeding a limit of 30.00