What is the amplitude, period, and phase shift of f(x) = −4 sin(2x + π) − 3? Amplitude = 4; period = π; phase shift: x equals pi over two Amplitude = −4; period = 2π; phase shift: x equals pi over two Amplitude = 4; period = π; phase shift: x equals negative pi over two Amplitude = −4; period = 2π; phase shift: x equals negative pi over two

The correct option is option (c)

Therefore amplitude = 4, period= π and

Step-by-step explanation:

Amplitude: The amplitude of a wave is a maximum displacement of a particle from its rest position

Period: The ratio of wavelength to the velocity.

Phase shift: The phase shift represents the amount a wave has shifted horizontally from the the usual position.

The equation of a wave is

f(x) = a sin(bx - c)+d

Where

amplitude = |a|

Given equation of wave is

f(x) = -4sin (2x + π) -3

Here a=-4, b=2, c = -π, d = -3

Amplitude = |-4| = 4

Therefore amplitude = 4, period= π and

it 2

step-by-step explanation:

8^1/3=2

c: lkllmn.

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