Consider the function f(x)=−x24+2f(x)=−x24+2. In this problem you will calculate ∫20(−x24+2)dx∫02(−x24+2)dx by using the definition ∫baf(x)dx=limn→[infinity][∑i=1nf(xi )Δx] ∫abf(x)dx=limn→[infinity][∑i=1nf(xi )Δx] The summation inside the brackets is RnRn which is the Riemann sum where the sample points are chosen to be the right-hand endpoints of each sub-interval. Calculate RnRn for f(x)=−x24+2f(x)=−x24+2 on the interval [0,2][0,2] and write your answer as a function of nn without any summation signs.

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step-by-step explanation:

should you really be posting this isn't math boi.

step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)  

ans789

step-by-step explanation: