What are the x- and y- coordinates of point P on the directed line segment from A to B such that P is One-third the length of the line segment from A to B? x = (StartFraction m Over m + n EndFraction) (x 2 minus x 1) + x 1 y = (StartFraction m Over m + n EndFraction) (y 2 minus y 1) + y 1 (1, 5) (0, 3) (–4, –5) (–5, –7)

true

explanation:

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this

i think the answer is seven, for if i'm being useless °ω°

step-by-step explanation: